min(self, axis: 'int | None | lib.NoDefault' = <no_default>, skipna=True, level=None, numeric_only=None, **kwargs)
If you want the index of the minimum, use idxmin
. This is the equivalent of the numpy.ndarray
method argmin
.
Axis for the function to be applied on.
Exclude NA/null values when computing the result.
If the axis is a MultiIndex (hierarchical), count along a particular level, collapsing into a scalar.
Include only float, int, boolean columns. If None, will attempt to use everything, then use only numeric data. Not implemented for Series.
Additional keyword arguments to be passed to the function.
Return the minimum of the values over the requested axis.
DataFrame.idxmax
Return the index of the maximum over the requested axis.
DataFrame.idxmin
Return the index of the minimum over the requested axis.
DataFrame.max
Return the maximum over the requested axis.
DataFrame.min
Return the minimum over the requested axis.
DataFrame.sum
Return the sum over the requested axis.
Series.idxmax
Return the index of the maximum.
Series.idxmin
Return the index of the minimum.
Series.max
Return the maximum.
Series.min
Return the minimum.
Series.sum
Return the sum.
>>> idx = pd.MultiIndex.from_arrays([This example is valid syntax, but we were not able to check execution
... ['warm', 'warm', 'cold', 'cold'],
... ['dog', 'falcon', 'fish', 'spider']],
... names=['blooded', 'animal'])
... s = pd.Series([4, 2, 0, 8], name='legs', index=idx)
... s blooded animal warm dog 4 falcon 2 cold fish 0 spider 8 Name: legs, dtype: int64
>>> s.min() 0See :
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